MCQ
Four boys and three girls stand in a queue for an interview, probability that they will in alternate position is
- A$\frac{1}{{34}}$
- ✓$\frac{1}{{35}}$
- C$\frac{1}{{17}}$
- D$\frac{1}{{68}}$
$\therefore $ The favourable cases $ = 4\,!\, \times \,3\,!$
Hence the required probability $=\frac{{ 4\,!\, \times 3\,!}}{{7\,!}} = \frac{6}{{7 \times 6 \times 5}} = \frac{1}{{35}}$.
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