Four conducting rods are joined to make a square. All rods are identical and ends $A, B$ and $C$ are maintained at given temperatures. choose $INCORRECT$ statement for given arrangement in steady state. (value of $\frac {KA}{L}$ is $1\frac{J}{{{S^o}C}}$ , symbols , have their usual meaning) 
  • AHeat current in $AB$ is equal to $1.5$ times of heat current in $BC$
  • BTemperature of end $D$ is $50\,^oC$ 
  • CHeat current in $AB$ is equal to heat current in $BC$
  • DHeat current withdrawn at end $B$ is $20\ J/S$
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