
of $PS$
${\therefore \quad PA = AS = L}$
${AR = AQ = \sqrt {{{(SR)}^2} + {{(AS)}^2}} }$
${ = \sqrt {{{(2L)}^2} + {{(L)}^2}} = L\sqrt 5 }$
Electric potential at point $A$ due to the given charge configuration is
$V_{A} =\frac{1}{4 \pi \varepsilon_{0}}\left[\frac{q}{P A}+\frac{q}{A S}+\frac{(-q)}{A Q}+\frac{(-q)}{A R}\right]$
$=\frac{1}{4 \pi \varepsilon_{0}}\left[\frac{q}{L}+\frac{q}{L}-\frac{q}{L \sqrt{5}}-\frac{q}{L \sqrt{5}}\right]$
$=\frac{1}{4 \pi \varepsilon_{0}}\left[\frac{2 q}{L}-\frac{2 q}{L \sqrt{5}}\right]=\frac{1}{4 \pi \varepsilon_{0}} \frac{2 q}{L}\left[1-\frac{1}{\sqrt{5}}\right]$




