Four equal capacitors, each of capacity $C$, are arranged as shown. The effective capacitance between $A$ and $B$ is
A$\frac{5}{8}\,C$
B$\frac{3}{5}\,C$
C$\frac{5}{3}\,C$
D$C$
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C$\frac{5}{3}\,C$
c (c) The given circuit can be simplified as follows
Equivalent capacitance between $A$ and $B$ is ${C_{AB}} = \frac{5}{3}\,C$
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