Four identical capacitors are connected in series with a $10\,V$ battery as shown. The point $N$ is earthed. The potentials of points $A$ and $B$ are
Medium
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As the all capacitance are same and in series so potential across each $=10 / 4=2.5 V$
now, $V_{A}-V_{N}=2.5+2.5+2.5=7.5$
or $V_{A}-0=7.5 \Rightarrow V_{A}=7.5 V$
and $V_{N}-V_{B}=2.5$
or $0-V_{B}=2.5$
or $V_{B}=-2.5 V$
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