MCQ
Four successive members of the first row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest $E^o_{M^{3+} /M^{2+}}$ value ?
- A$Cr\,(Z=24)$
- B$Mn\,(Z = 25)$
- C$Fe\,(Z=26)$
- ✓$Co\,(Z = 27)$
$\mathrm{E}^{0}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}=+0.77 \,\mathrm{V}$
$\mathrm{E}^{0}_{\mathrm{Co}^{3+} / \mathrm{Co}^{2+}}=+1.97\, \mathrm{V}$
$E^{0}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}=+1.57\, \mathrm{V}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$X\xrightarrow{{{\text{Bromination}}}}Y\xrightarrow{{NaN{O_2} + HCl}}Z\mathop {\xrightarrow{{{\text{Boiling}}}}}\limits_{{C_2}{H_5}OH} {\text{Tribromobenzene}}$
$Al_{(s)}\, | Al^{+3}\, (0.1\,M)||Fe^{+2}\, (0.001\,M)|Fe_{(s)}$
If $E_{A{l^{ + 3}}/Al}^o = - 1.66\,V$ and $E_{Fe/F{e^{ + 2}}}^o = + 0.44\,V$
$C{H_3} - CH = CH - COOH\xrightarrow{{B{r_2}}}$