MCQ
$\frac{\cos 28^{\circ}}{\sin 62^{\circ}}=?$
- A$2$
- B$-1$
- C$0$
- ✓$1$
✓
Answer
Correct option: D.
$1$
$\frac{\cos 28^{\circ}}{\sin 62^{\circ}} $
$=\frac{\sin \left(90^{\circ}-28^{\circ}\right)}{\sin 62^{\circ}} $
$=\frac{\sin 62^{\circ}}{\sin 62^{\circ}} $
$=1$
$=\frac{\sin \left(90^{\circ}-28^{\circ}\right)}{\sin 62^{\circ}} $
$=\frac{\sin 62^{\circ}}{\sin 62^{\circ}} $
$=1$
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