We have: x 2 + x 3 + x 4 =13 L.C.M. of 2, 3, 4 = 12 x 2 + x 3 + x 4 =13 6x+4x+3x=13 12 13x=156 13x 13 =156 13 (Dividing both sides by 13) =12 =12 Verification: L.H.S= x 2 + x 3 + x 4 =12 2 +12 3 +12 4 =6+4+3 =13=R.H.S

x 2 + x 3 + x 4 =13

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$\frac{\text{x}}{2}+\frac{\text{x}}{3}+\frac{\text{x}}{4}=13$

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Answer

We have:$\frac{\text{x}}{2}+\frac{\text{x}}{3}+\frac{\text{x}}{4}=13$
L.C.M. of 2, 3, 4 = 12
$\therefore\frac{\text{x}}{2}+\frac{\text{x}}{3}+\frac{\text{x}}{4}=13$
$6\text{x}+4\text{x}+3\text{x}=13\times12$
$\Rightarrow13\text{x}=156$
$\frac{13\text{x}}{13}=\frac{156}{13}$ (Dividing both sides by 13)
$\Rightarrow\text{x}=12$
$\therefore\text{x}=12$
Verification:
$\text{L.H.S}=\frac{\text{x}}{2}+\frac{\text{x}}{3}+\frac{\text{x}}{4}$
$=\frac{12}{2}+\frac{12}{3}+\frac{12}{4}=6+4+3$
$=13=\text{R.H.S}$

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