MCQ
From a cross $AABb × aaBb$, the genotypes $AaBB : AaBb : Aabb : aabb$ will be obtained in the following ratio
- A$1 : 1 : 1 : 1$
- ✓$1 : 2 : 1 : 0$
- C$0 : 3 : 1 : 0$
- D$1 : 1 : 1 : 0$
$AABb × aaBb$
|
|
$AB$ |
$Ab$ |
$AB$ |
$Ab$ |
|
$aB$ |
$AaBB$ |
$AaBb$ |
$AaBB$ |
$AaBb$ |
|
$ab$ |
$AaBb$ |
$Aabb$ |
$AaBb$ |
$Aabb$ |
|
$aB$ |
$AaBB$ |
$AaBb$ |
$AaBB$ |
$AaBb$ |
|
$ab$ |
$AaBb$ |
$Aabb$ |
$AaBb$ |
$Aabb$ |
$AaBB : AaBb : Aabb : aabb :$
$ 4 : 8 : 4 : 0$
$AaBB = 1; AaBb = 2; Aabb = 1; aabb = 0$
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