Question
From a solid right circular cylinder with height $10\ cm$ and radius of the base $6\ cm$, a right circular cone of the same height and base is removed. Find the volume of the remaining solid. $\big(\text{Take}\ \pi=3.14\big).$

Answer

Here, height $(h) = 10cm$ and radius $= 6cm$
$\therefore$ Volume of the remaining solid
$=(\pi\text{r}^2\text{h})-\Big(\frac{1}{3}\pi\text{r}^2\text{h}\Big)$
$=\big(\pi\times6\times6\times10\big)\text{cm}^3$
$-\Big(\frac{1}{3}\pi\times6\times6\times10\Big)\text{cm}^3$
$=\frac{2}{3}\pi\times6\times6\times10\text{cm}^3$
$=\Big(\frac{2}{3}\times3.14\times360\Big)\text{cm}^3=753.6\text{cm}^3$
$\therefore$ Volume of the remaining solid $753.6cm^3.$

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