MCQ
From eighty cards numbered $1$ to $80$, two cards are selected randomly. The probability that both the cards have the numbers divisible by $4$ is given by
- A$\frac{{21}}{{316}}$
- ✓$\frac{{19}}{{316}}$
- C$\frac{1}{4}$
- DNone of these
and favorable ways ${ = ^{20}}{C_2}$
$\therefore$ Required probability $P = \frac{{^{20}{C_{_2}}}}{{^{80}{C_2}}} = \frac{{19}}{{316}}$.
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