MCQ
From left to right, $sp^2,\, sp^2,\, sp,\, sp$ hybridisation is present in
- ✓$CH_2=CH-C \equiv N$
- B$CH_2=C=CH-CH_3$
- C$HC\equiv C-C\equiv CH$
- D$CH\equiv C-CH=CH_2$
✓
Answer
Correct option: A.
$CH_2=CH-C \equiv N$
a
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