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1. units,dimensions and measurement — Physics STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 SciencePhysics1. units,dimensions and measurement1 Mark
MCQ
From the dimensional consideration, which of the following equation is correct
  • ✓
    $T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
  • B
    $T = 2\pi \sqrt {\frac{{GM}}{{{R^3}}}} $
  • C
    $T = 2\pi \sqrt {\frac{{GM}}{{{R^2}}}} $
  • D
    $T = 2\pi \sqrt {\frac{{{R^2}}}{{GM}}} $
✓

Answer

Correct option: A.
$T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
a
(a) By substituting the dimensions in $T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $

we get $\sqrt {\frac{{{L^3}}}{{{M^{ - 1}}{L^3}{T^{ - 2}} \times M}}} = T$

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