(B) It has to be kept away from dust as it decomposes in presence of dust. Thus, the option (B) is correct.
(C) Hydrogen peroxide can act as oxidizing as well as reducing agent. For example, in acidic medium, it oxidizes ferrous ions to ferric ions. $2 \mathrm{Fe}^{2+}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+} \rightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O}$
In acidic medium, hydrogen peroxide reduces HOCI to chloride ion. $\mathrm{HOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}^{+}+\mathrm{Cl}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
Thus, the option $C$ is incorrect.
(D) It decomposes on exposure to light to form water and oxygen. $2 \mathrm{H}_{2} \mathrm{O}_{2} \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
Thus, the option (D) is correct.
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$\mathrm{V}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{V} \ \ \ \ \mathrm{E}^0=-1.19 \mathrm{~V} $
$\mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \ \ \ \ \mathrm{E}^0=-0.04 \mathrm{~V} $
$\mathrm{Au}^{3+}(\mathrm{aq})+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \ \ \ \ \mathrm{E}^0=+1.40 \mathrm{~V} $
$\mathrm{Hg}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg} \ \ \ \ \mathrm{E}^0=+0.86 \mathrm{~V}$
The pair$(s)$ of metals that is$(are)$ oxidized by $\mathrm{NO}_3^{-}$in aqueous solution is$(are)$
$(A)$ $\mathrm{V}$ and $\mathrm{Hg}$ $(B)$ $\mathrm{Hg}$ and $\mathrm{Fe}$
$(C)$ $\mathrm{Fe}$ and $\mathrm{Au}$ $(D)$ $Fe$ and $V$