Question
From the formula $B = 2a^2 – b^2,$ calculate the value of $B$ when $a = 3$ and $b = − 1.$

Answer

$B = 2a^2 – b^2$
Put the values of $a = 3$ and $b = − 1$ in above equation
$B = 2 \times (3)^2 – (− 1)^2$
$B = 18 – 1$
$B = 17$
Value of $B$ is $= 17$

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