MCQ
Fructose reduces Tollen's reagent due to
- Aasymmetric carbons
- Bprimary alcoholic group
- Csecondary alcoholic group
- ✓enolisation of fructose followed by conversion to aldehyde by base
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$(A)$ The stronger the temperature dependence of the rate constant, the higher is the activation energy.
$(B)$ If a reaction has zero activation energy, its rate is independent of temperature.
$(C)$ The stronger the temperature dependence of the rate constant, the smaller is the activation energy.
$(D)$ If there is no correlation between the temperature and the rate constant then it means that the reaction has negative activation energy.
$Xe{{F}_{6}}\,\xrightarrow{+\,Excess\,\,{{H}_{2}}O}\,'X'\,+\,HF$
$Xe{{F}_{6}}\,\xrightarrow{+\,2\,\,{{H}_{2}}O}\,'Y'\,+\,HF$
