Function f(x) = x^2 - 1 x^3 - 1 is not defined at x = 1, then the… - Vidyadip

MCQ

Function $f(x) = \frac{{{x^2} - 1}}{{{x^3} - 1}}$is not defined at $x = 1$, then the value of $f(1)$ when function is continuous at $x = 1$, will be

A
$ - \frac{3}{2}$
✓
$\frac{2}{3}$
C
$\frac{3}{2}$
D
$ - \frac{2}{3}$

✓

Answer

Correct option: B.

$\frac{2}{3}$

b
(b) $f(x) = \frac{{{x^2} - 1}}{{{x^3} - 1}} = \frac{{(x - 1)\,(x + 1)}}{{(x - 1)\,({x^2} + x + 1)}}\, \Rightarrow f(1) = \frac{2}{3}$.

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