Question
Function f(x) = x3 - 27x + 5 is monotonically increasing when:
- $\text{x}<-3$
- $|\text{x}|>3$
- $\text{x}\leq-3$
- $|\text{x}|\geq3$
Solution:
f(x) = 3x2 - 27x
⇒ f'(x) = x3 - 27x + 5
⇒ f'(x) = 3(x2 - 9)
Function is increasing,
$3\big(\text{x}^2-9\big)\geq0$
$\Rightarrow\text{x}^2\geq9$
$\Rightarrow|\text{x}|\geq3$
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The corner points of the feasible region determined by the following system of linear inequalities:
2x + y ≤ 10, x + 3y ≤ 15, x, y ≥ 0 are (0, 0), (5, 0), (3, 4) and (0, 5).
Let Z = px + qy, where p.q > 0.
Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is: