MCQ
Function $f(x)={\left( {1 + \frac{1}{x}} \right)^x}$ then Domain of $f (x)$ is
- A$(-1, 0) \cup (0, \infty )$
- B$R - { 0 }$
- ✓$(-\infty , -1) \cup (0, \infty )$
- D$(0, \infty )$
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The solution of the equation $(2\text{y}-1)\text{dx}-(2\text{x}+3)\text{dy}=0$ is:
$\frac{2\text{x}-1}{2\text{y}+3}=\text{k}$
$\frac{2\text{y}+1}{2\text{x}-3}=\text{k}$
$\frac{2\text{x}+3}{2\text{y}-1}=\text{k}$
$\frac{2\text{x}-1}{2\text{y}-1}=\text{k}$