10. Biomolecules — Chemistry STD 12 Science — Question

$Zn + HN{O_3}(Dilute)\, \to \,Zn{(N{O_3})_2} + P\, \uparrow $

Reason : $Zn$ is deposited at anode, and $Cu$ is deposited at cathode.

$(A)\,Cu$ $(II)$ complexes are always paramagnetic

$(B)\,Cu$ $(I)$ complexes are generally colourless

$(C)\,Cu$ $( I )$ is easily oxidized

$(D)$ In Fehling solution, the active reagent has $Cu$ $( I )$