MCQ
Galileo writes that for angles of projection of a projectile at angles $(45 + \theta )$ and $(45 - \theta )$, the horizontal ranges described by the projectile are in the ratio of (if $\theta \le 45)$
- A$2:1$
- B$1:2$
- ✓$1:1$
- D$2:3$
For angle $(45^\circ + \theta )$, $R = \frac{{{u^2}\sin (90^\circ + 2\theta )}}{g} = \frac{{{u^2}\cos 2\theta }}{g}$
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