MCQ
Galileo writes that for angles of projection of a projectile at angles $(45 + \theta )$ and $(45 - \theta )$, the horizontal ranges described by the projectile are in the ratio of (if $\theta \le 45)$
  • A
    $2:1$
  • B
    $1:2$
  • $1:1$
  • D
    $2:3$

Answer

Correct option: C.
$1:1$
c
(c) For angle $(45^\circ - \theta )$, $R = \frac{{{u^2}\sin (90^\circ - 2\theta )}}{g} = \frac{{{u^2}\cos 2\theta }}{g}$

For angle $(45^\circ + \theta )$, $R = \frac{{{u^2}\sin (90^\circ + 2\theta )}}{g} = \frac{{{u^2}\cos 2\theta }}{g}$

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