MCQ
Gasoline has composition
- A${C_8} - {C_{12}}$
- B${C_2} - {C_5}$
- ✓${C_6} - {C_{11}}$
- DNone of these
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$C{H_3}C{H_2}C{H_2}OH \xrightarrow{PCl_3}A\xrightarrow{Alco.KOH}B$
$(1)$ $\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\, \\
{{H}_{3}}C-C-C{{H}_{2}}-Cl \\
\end{matrix}$
$(2)$ ${{H}_{2}}C-C{{H}_{2}}-C{{H}_{2}}-Cl$
$(3)$ ${{({{H}_{3}}C)}_{3}}C-Cl$
$S + HNO_3 \rightarrow H_2SO_4 + 6NO_2 + 2H_2O$
Reason : Oxidation takes place at anode and reduction at cathode.
