MCQ
Gem dihalide on hydrolysis gives:
- AVic diol
- BGem diol
- ✓Carbonyl compound
- DCarboxylic acid
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$Z\,\xrightarrow{{PC{l_5}}}\,X\,\xrightarrow[\Delta ]{{{\text{Alc}}{\text{.KOH}}}}\,Y\,\xrightarrow{{{H_2}O/{H^ \oplus }}}\,\mathop Z\limits_{{\text{(Major)}}} \,,\,\,Z$ is
(Molecular wight of $HA= 60, \,d_{solution} = 1\,gm/ml$)
$6 OH ^{-}+ Cl ^{-} \rightarrow ClO _{3}^{-}+3 H _{2} O +6 e ^{-}$
If only $60 \%$ of the current is utilized in the reaction, the time (rounded to the nearest hour) required to produce $10\, g$ of $KCIO _{3}$ using a current of $2\, A$ is..........
(Given : $F =96,500\, C\, mol ^{-1}$ molar mass of $\left. KClO _{3}=122\,gmol ^{-1}\right)$