- A${C_n}{H_{2n}}$
- B${C_n}{H_{2n - 2}}$
- ✓${C_n}{H_{2n + 2}}$
- D${C_{2n}}{H_{2n}}$
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$A$. Compound ' $B$ ' is aromatic
$B$. The completion of above reaction is very slow
$C$. '$A$' shows tautomerism
$D$. The bond lengths $C - C$ in compound $B$ are found to be same
Choose the correct answer from the options given below :
$(I)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C{H_2} - O - S - C{F_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}$
$(II)$ $CH_3-CH_2-O-TsCl$
$(III)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_3}} \\
{|\,\,\,\,} \\
{OH\,}
\end{array}$
$(IV)$ $\begin{array}{*{20}{c}}
{C{H_3} - CH - OH} \\
| \\
{{C_6}{H_5}}
\end{array}$
