MCQ
General solution of $\tan 5\theta = \cot 2\theta $ is $($ where $n \in Z )$
- ✓$\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$
- B$\theta = \frac{{n\pi }}{7} + \frac{\pi }{5}$
- C$\theta = \frac{{n\pi }}{7} + \frac{\pi }{2}$
- D$\theta = \frac{{n\pi }}{7} + \frac{\pi }{3}$