MCQ
General solution of $\tan 5\theta = \cot 2\theta $ is  $($ where $n \in Z )$
  • $\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$
  • B
    $\theta = \frac{{n\pi }}{7} + \frac{\pi }{5}$
  • C
    $\theta = \frac{{n\pi }}{7} + \frac{\pi }{2}$
  • D
    $\theta = \frac{{n\pi }}{7} + \frac{\pi }{3}$

Answer

Correct option: A.
$\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$
a
(a) $\tan 5\theta = \tan \left( {\frac{\pi }{2} - 2\theta } \right)$ 

$ \Rightarrow $ $5\theta = n\pi + \frac{\pi }{2} - 2\theta $

$ \Rightarrow $ $7\theta = n\pi + \frac{\pi }{2}$

$ \Rightarrow $ $\theta = \frac{{n\pi }}{7} + \frac{\pi }{{14}}$.

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