MCQ
General solution of $\tan5\text{x}=\cot2\text{x}$ is:
  • A
    $\frac{\text{n}\pi}{7}+\frac{\pi}{2},\ \text{n}\in\text{Z}$
  • B
    $\text{x}=\frac{\text{n}\pi}{7}+\frac{\pi}{3},\ \text{n}\in\text{Z}$
  • $\text{x}=\frac{\text{n}\pi}{7}+\frac{\pi}{14},\ \text{n}\in\text{Z}$
  • D
    $\text{x}=\frac{\text{n}\pi}{7}=\frac{\pi}{14},\ \text{n}\in\text{Z}$

Answer

Correct option: C.
$\text{x}=\frac{\text{n}\pi}{7}+\frac{\pi}{14},\ \text{n}\in\text{Z}$
Given:
$\tan5\text{x}=\cot2\text{x}$
$\Rightarrow\tan5​\text{x}=\tan\Big(\frac{\pi}{2}-2\text{x}\Big)$
$\Rightarrow5\text{x}=\text{n}\pi+\frac{\pi}{2}-2\text{x}$
$\Rightarrow7\text{x}=\text{n}\pi+\frac{\pi}{2}$
$\Rightarrow\text{x}=\frac{\text{n}\pi}{7}+\frac{\pi}{14},\ \text{n}\in\text{Z}$

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