Question
Give four rational numbers equivalent to$\frac{-2}{7}$
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Answer
Four rational numbers equivalent to $\frac{-2}{7}$are
$\frac{-2 \times 2}{7 \times 2}=\frac{-4}{14}$, $\frac{-2 \times 3}{7 \times 3}=\frac{-6}{21}$
$\frac{-2 \times 4}{7 \times 4}=\frac{-8}{28}$and $\frac{-2 \times 5}{7 \times 5}=\frac{-10}{35}$
$\therefore$$\frac{-4}{14}, \frac{-6}{21}, \frac{-8}{28}$ and $\frac{-10}{35}$ are four rational numbers equivalent to $\frac{-2}{7}$
$\frac{-2 \times 2}{7 \times 2}=\frac{-4}{14}$, $\frac{-2 \times 3}{7 \times 3}=\frac{-6}{21}$
$\frac{-2 \times 4}{7 \times 4}=\frac{-8}{28}$and $\frac{-2 \times 5}{7 \times 5}=\frac{-10}{35}$
$\therefore$$\frac{-4}{14}, \frac{-6}{21}, \frac{-8}{28}$ and $\frac{-10}{35}$ are four rational numbers equivalent to $\frac{-2}{7}$
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