Question
Give reason:
(i) Transition elements exhibit higher enthalpies of atomisation.
(ii) In aqueous solution, $Cr ^{2+}$ is stronger reducting agent than $Fe ^{2+}$.
(iii) The second ionisation enthalpy of Cu is higher then $Z n$.

Answer

→ (i) Because transition elements have more unpaired electrons, they have stronger interatomic interactions and hence stronger bonding. so....
→ (ii) In $Cr ^{2+}$ to $Cr ^{3+} d ^4 \rightarrow d ^3$ occurs and in $Fe ^{2+}$ to $Fe ^{3+} d ^6 \rightarrow d ^5$ occurs. In aq. medium $d ^3$ is more stable than $d^5$.
→ (iii) In 2nd ionisation enthalpy of $Cu e ^{-}$is removed from $3 d^{10}$ and in Zn from $4 s^1 .3 d^{10}$ is more stable configuration than $4 s^1$.

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