Gujarat BoardEnglish MediumSTD 12 ScienceChemistrySurface Chemistry1 Mark
Question
Give the expression of Freundlich isotherms.
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Answer
$\frac{\text{x}}{\text{m}}=\text{kp}^\frac{1}{\text{n}}\ \ \ \ \ \ \text{or}\ \ \ \ \ \ \text{log}\frac{\text{x}}{\text{m}}=\text{log k}+\frac{1}{\text{n}}\text{log p}$
where m is the mass of the adsorbent and x is the mass of adsorbate, p is the pressure of the gas and n is an integer.
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