Question
Give the feature of prohibition by explaining the logical form of ‘~’.
| 1 | 2 | |
| p | ~ p | |
| 1 | T | F |
| 2 | F | T |
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| $T \rightarrow B$ |
| $B \rightarrow ( \sim\ P \rightarrow\ \sim\ Q)$ |
| $\sim\ P\ \&\ \sim\ R$ |
| $T$ |
| $\therefore\sim\ Q\ v\ X$ |
| $A \rightarrow J$ |
| $B \rightarrow R$ |
| $(A\ v\ B)\&\ \sim D$ |
| $J \rightarrow D$ |
| $\therefore (D\ v\ R)\ \&\ (B\ v\ K)$ |
| $(A\ \&\ B)\ \rightarrow\ P$ |
| $\sim\ P\ \&\ \sim\ Q$ |
| $(J\ \rightarrow\ K)\ \rightarrow\ Q$ |
| $\sim\ (A\ \&\ B)\ \&\ \sim\ (J\ \rightarrow\ K)$ |
| $(A\ v\ B)\ \rightarrow\ D$ |
| $E\ \rightarrow\ \sim\ D$ |
| $(G\ \leftrightarrow\ F)\ \rightarrow\ (E\ \&\ H)$ |
| $G\ \leftrightarrow\ F$ |
| $\sim\ (A\ v\ B)\ \&\ H$ |