Question
Given 4k + 1 = 13, find the values of:
(a) 8k+ 2
(b) 4k
(c) k
(d) 4k – 1
(e) -k – 2
(a) 8k+ 2
(b) 4k
(c) k
(d) 4k – 1
(e) -k – 2
✓
Answer
4k + 1 = 13
Subtract 1 from both sides
4k + 1 – 1 = 13 – 1
⇒ 4k = 12
Divide both sides by 4
4k ÷ 4 = 12 ÷ 4
⇒ k = 3
(a) 8k + 2 = 8(3)+ 2
= 24 + 2
= 26
(b) 4k = 4 × 3 = 12
(c) k = 3
(d) 4k – 1 = 4(3) – 1
= 12 – 1
= 11
(e) -k – 2 = -3 – 2 = -5
Subtract 1 from both sides
4k + 1 – 1 = 13 – 1
⇒ 4k = 12
Divide both sides by 4
4k ÷ 4 = 12 ÷ 4
⇒ k = 3
(a) 8k + 2 = 8(3)+ 2
= 24 + 2
= 26
(b) 4k = 4 × 3 = 12
(c) k = 3
(d) 4k – 1 = 4(3) – 1
= 12 – 1
= 11
(e) -k – 2 = -3 – 2 = -5
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