Question
Given $A=\left[\begin{array}{ll}4 & 1 \\ 2 & 3\end{array}\right]$ and $B=\left[\begin{array}{cc}1 & 0 \\ -2 & 1\end{array}\right]$ Find $A^2$
✓
Answer
$A^2=\left[\begin{array}{ll}4 & 1 \\ 2 & 3\end{array}\right]\left[\begin{array}{ll}4 & 1 \\ 2 & 3\end{array}\right] $
$ =\left[\begin{array}{cc}16+2 & 4+3 \\ 8+6 & 2+9\end{array}\right] $
$=\left[\begin{array}{cc}18 & 7 \\ 14 & 11\end{array}\right]$
$ =\left[\begin{array}{cc}16+2 & 4+3 \\ 8+6 & 2+9\end{array}\right] $
$=\left[\begin{array}{cc}18 & 7 \\ 14 & 11\end{array}\right]$
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