Question
Given $\angle\text{POR}=3\text{x}$ and $\angle\text{QOR}=2\text{x}+10,$ Find the value of x for which POQ will be a line. (Figure 10.41).
✓
Answer
For the case that POR is a line$\angle\text{POR}$ and $\angle\text{QOR}$ are linear parts
$\angle\text{POR}+\angle\text{QOR}=180^\circ$
Also, given that,$\angle\text{POR}=3\text{x}$ and $\angle\text{QOR}=2\text{x}+10$
2x + 10 + 3x = 180 5x + 10 = 180 5x = 180 - 10 5x = 170 x = 34 Hence the value of x is 34°
$\angle\text{POR}+\angle\text{QOR}=180^\circ$
Also, given that,$\angle\text{POR}=3\text{x}$ and $\angle\text{QOR}=2\text{x}+10$
2x + 10 + 3x = 180 5x + 10 = 180 5x = 180 - 10 5x = 170 x = 34 Hence the value of x is 34°
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