$A$. $Al^{3+}$ $B$. $Cu^{2+}$ $C$. $Ba^{2+}$ $D$. $Co^{2+}$ $E$. $Mg^{2+}$
Choose the correct answer from the options given below.
| Group | Cations |
| Group $-II$ | $\mathrm{Cu}^{2+}$ |
| Group $-III$ | $\mathrm{Al}^{3+}$ |
| Group $-IV$ | $\mathrm{Co}^{2+}$ |
| Group $-V$ | $\mathrm{Ba}^{2+}$ |
| Group $-VI$ | $\mathrm{Mg}^{2+}$ |
The correct order of group number of ions is $\underset{\text { (B) }}{\mathrm{Cu}^{2+}} < \underset{\text { (A) }}{\mathrm{Al}^{3+}} < \underset{\text { (D) }}{\mathrm{Co}^{2+}} < \underset{\text { (C) }}{\mathrm{Ba}^{2+}} < \underset{\text { (E) }}{\mathrm{Mg}^{2+}}$
$\therefore$ The correct order is $\mathrm{B}, \mathrm{A}, \mathrm{D}, \mathrm{C}, \mathrm{E}$
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$(1)$ It is reduced to methyl phenyl carbinol by sodium and ethanol
$(2)$ It is oxidised to benzoic acid with acidified $KMn{O_4}$
$(3)$ It does not undergo iodoform electrophilic substitution like nitration at meta position
$(4)$ It does not undergo iodoform reaction with iodine and alkali
${N_2}(g) + {O_2}(g) \rightleftharpoons 2NO(g)$
${N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g)$
${N_2}(g) + 3{H_2}(g) \rightleftharpoons 2N{H_3}(g)$