Given below are two statements:
Statement $I :$ Aniline is less basic than acetamide.
Statement $II :$ In aniline, the lone pair of electrons on nitrogen atom is delocalised over benzene ring due to resonance and hence less available to a proton.
Choose the most appropriate option:
JEE MAIN 2021, Difficult
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionIncorrect match is
- 2View SolutionAcetonitrile is:
- 3View SolutionProduct and name of the reaction is
- 4View SolutionWhich of the following will not given Hoffmann bromamide rection ?
- 5View SolutionFluorescein is an example of
- 6$\xrightarrow[{HCl}]{{NaN{O_2}}}\,(A)$ product of this reaction isView Solution
- 7View SolutionThe major product for the following reaction is:
- 8A positive carbylamine test is given by :-View Solution
$(a)$ $N,N-$ Dimethylaniline
$(b)$ $2,4 -$ Dimethylaniline
$(c)$ $N -$ methy $l-o-$ methylaniline
$(d)$ $p -$ Methylbenzylamine
- 9Product $(A)$ of the above reaction isView Solution
- 10In the chemical reactions, the compounds $'A'$ and $'B'$ respectively areView Solution
