MCQ
Given below are two statements :

Statement $I :$ The limiting molar conductivity of $\mathrm{KCl}$ (strong electrolyte) is higher compared to that of $\mathrm{CH}_{3} \mathrm{COOH}$ (weak electrolyte).

Statement $II :$ Molar conductivity decreases with decrease in concentration of electrolyte.

In the light of the above statements, choose the most appropriate answer from the options given below:

  • A
    Statement $I$ is true but Statement $II$ is false.
  • B
    Statement $I$ is false but Statement $II$ is true.
  • C
    Both Statement $I$ and Statement $II$ are true.
  • Both Statement $I$ and Statement $II$ are false.

Answer

Correct option: D.
Both Statement $I$ and Statement $II$ are false.
d
$Ion$ $\mathrm{H}^{+}$ $\mathrm{K}^{+}$ $\mathrm{Cl}^{-}$ $\mathrm{CH}_{3} \mathrm{COO}^{-}$
$\Lambda_{\mathrm{m} \mathrm{Sem}^{2} / \mathrm{mole}}^{\infty}$ $349.8$ $73.5$ $76.3$ $40.9$

So $\Lambda_{\mathrm{m} \mathrm{CH}_{3} \mathrm{COOH}}^{\infty}=\Lambda_{\mathrm{m}\left(\mathrm{H}^{+}\right)}^{\infty}+\Lambda_{\mathrm{m} \mathrm{CH}_{3} \mathrm{COO}^{-}}^{\infty}$

$=349.8+40.9$

$=390.7\, \mathrm{Scm}^{2} / \mathrm{mole}$

$\Lambda_{\mathrm{m} \mathrm{KCl}}^{\infty}= \Lambda_{\mathrm{m}\left(\mathrm{K}^{*}\right)}^{\infty}+\Lambda_{\mathrm{m}(\mathrm{Cl}^{-})}^{\infty})$

$= 73.5+76.3$

$= 149.3\, \mathrm{Scm}^{2} / \mathrm{mole}$

So statement$-I$ is wrong or False.

As the concentration decreases, the dilution increases which increases the degree of dissociation, thus increasing the no. of ions, which increases the molar conductance.

So statement$-II$ is false.

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