MCQ
Given below are two statements:

Statements$-I :$ In Hofmann degradation reaction, the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom.

Statement$-II :$ The group is migrated in Hofmann degradation reaction to electron deficient atom.

In the light of the above statement, choose the most appropriate answer from the options given below

  • A
    Both Statement$-I$ and Statement$-II$ are correct
  • B
    Both Statement$-I$ and Statement$-II$ are incorrect
  • C
    Statement$-I$ is correct but Statement$-II$ is incorrect
  • Statement$-I$ is incorrect but Statement$-II$ is correct

Answer

Correct option: D.
Statement$-I$ is incorrect but Statement$-II$ is correct
d
$R - CO - NH _{2}+ Br _{2}+ NaOH \rightarrow$

$R - NH _{2}+ Na _{2} CO _{3}+ NaBr + H _{2} O$

$R - CO - NH _{2}+\overline{ O }H \rightarrow R - CO -\overline{ N }H \stackrel{ Br _{2}}{\longrightarrow}$

$R - CO - NH - Br \stackrel{ OH ^{-}}{\longrightarrow} R - CO -\overline{ N }- Br$

$\stackrel{\text { migration of } \overline{ R }}{\longrightarrow} R - NCO \stackrel{2 \overline{O}H}{\longrightarrow} RNH _{2}+ CO _{3}^{2-}$

In this reaction of alkyl as well as aryl group can migrate to electron deficient nitrogen atom.

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