Question
Given below is the frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for $30$ days.
Concentration of $\mathrm{SO}_2$
$0.00 - 0.04$
$0.04 - 0.08$
$0.08 - 0.12$
$0.12 - 0.16$
$0.16 - 0.20$
$0.20 - 0.24$
No. of days
$4$
$8$
$9$
$2$
$4$
$3$
Find the probability of the concentration of sulphur dioxide in the interval $0.12 - 0.16$ on any of these days.

Answer

Total no of days: $30$ Probability of concentration of $\mathrm{SO}_2$ in interval $0.12 - 0.16$
$=\frac{\text{Favorable out come}}{\text{Total out come}}$
$=\frac{2}{30}$
$=\frac{1}{15}$
$=0.06$

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