MCQ
Given electrode potentials :
$Fe^{3+} + e \to Fe^{2+} ;$ $E^o = 0.771\, volts$
$I_2 + 2e\to 2I^-;$ $E^o = 0.536\, volts$
$E^o$ cell for the cell reaction
$2Fe^{3+} + 2I^-\to 2Fe^{2+} + I_2$ is
- A$(2 \times 0.771 -0.536) = 1.006 \,volts$
- B$(0.771 -0.5 \times 0.536) = 0.503 \,volts$
- ✓$0.771 -0.536 = 0.235\, volts$
- D$0.536 -0.771 = -0.235 \,volts$
