MCQ
Given electrode potentials
$Fe^{3+} + e \to Fe^{2+}\, ;\, E^o = 0.771\,volt$
$I_2 + 2e \to 2I^-\, ;\, E^o = 0.536\,volt$
$E^o$ cell for the cell reaction
$2Fe^{3+} + 2I^-\to 2Fe^{2+}+ I_2$ is
- A$(2 \times 0.771 -0.536) = 1.006\,volt$
- B$(0.771 -0.5 \times 0.536) = 0.503\,volt$
- ✓$(0.771 -0.536) = 0.235\,volt$
- D$(0.536 -0.771) = -0.235\,volt$
