MCQ
Given :

$E^o_{Cr^{3+}/Cr} =-0.74\, V,\,$ $E^o_{MnO_4^-/Mn^{2+}} =1.51 \,V$

$E^o_{Cr_2O_7^{2-}/Cr^3+} =1.33\,V:$ $E^o_{Cl/Cl^-} =1.36\,V$

Based on the data given above, strongest oxidising agent will be :

  • A
    $Cl$
  • B
    $Cr^{3+}$
  • C
    $Mn^{2+}$
  • $MnO_4^-$

Answer

Correct option: D.
$MnO_4^-$
d
Higher the value of standard reduction potential stronger will be the oxidising agent, hence $M n O_{4}^-$ is the strongest oxidising agent.

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