MCQ
Given

$(i)$ $\begin{gathered}
  HCN\left( {aq} \right) + {H_2}O\left( l \right) \rightleftharpoons {H_3}{O^ + }\left( {aq} \right) + C{N^ - }\left( {aq} \right) \hfill \\
  {K_a} = 6.2 \times {10^{ - 10}} \hfill \\ 
\end{gathered} $

$(ii)$ $\begin{gathered}
  C{N^ - }\left( {aq} \right) + {H_2}O\left( l \right) \rightleftharpoons HCN\left( {aq} \right) + O{H^ - }\left( {aq} \right) \hfill \\
  {K_b} = 1.6 \times {10^{ - 5}} \hfill \\ 
\end{gathered} $

These equilibria show the following order of the relative base strength

  • A
    $O{H^ - } > {H_2}O > C{N^ - }$
  • $O{H^ - } > C{N^ - } > {H_2}O$
  • C
    ${H_2}O > C{N^ - } > O{H^ - }$
  • D
    $C{N^ - } > {H_2}O > O{H^ - }$

Answer

Correct option: B.
$O{H^ - } > C{N^ - } > {H_2}O$
b
The more is the value of equilibrium constant, the more is the completion of  reaction or more is the concentration of products i.e . the order of relative strength would be

$O{H^ - } > C{N^ - } > {H_2}O$

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