Question
Given that $\frac{a^3+3 a b^2}{b^2+3 a^2 b}=\frac{63}{62}$.
Using Componendo and Dividendo find $a : b.$

Answer

We have
$\frac{a^3+3 a b^2}{b^2+3 a^2 b}=\frac{63}{62}$
App. compoenedo and dividendo
$\frac{a^3+3 a b^2+b^3+3 a^2 b}{a^3+3 a b^2-b^3-3 a^2 b}=\frac{63+62}{63-62} $
$ \frac{a^3+3 a b^2+b^3+3 a^2 b}{a^3+3 a b^2-b^3-3 a^2 b}=\frac{125}{1}$
$ \frac{(a+b)^3}{(a-b)^3}=\frac{125}{1} $
$ \frac{a+b}{a-b}=\frac{5}{1}$
Again Applying Componendo & Dividendo
$\frac{a+b+a-b}{a+b-a+b}=\frac{5+1}{5-1} $
$ \frac{2 a}{2 b}=\frac{6}{4}$
$ a : b =3: 2$

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