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Real Numbers — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsReal Numbers1 Mark
Question
Given that HCF (306. 657) = 9, find LCM (306, 657).
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Answer

By the property that LCM × HCF = Product of the two numbers
LCM × 9 = 306 × 657
LCM $=\frac{306\times 657}{9}= 22338$
Therefore LCM (306, 657) = 22338.

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