$\Lambda_{ m }^{\alpha}=133.4\,\left( AgNO _{3}\right) ; \Lambda_{ m }^{\alpha}=149.9( KCl )$
$\Lambda_{ m }^{\alpha}=144.9\, S\, cm ^{2} \,mol ^{-1}\left( KNO _{3}\right)$
the molar conductivity at infinite dilution for $AgCl$ is $.......\, S \,cm ^{2}\, mol ^{-1}$
$=133.4+149.9-144.9$
$=138\, S \,cm ^{2}\, mol ^{-1}$
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Reason: Due to formation of a complex
| List$-I$ | List$-II$ | ||
| $(a)$ | Sucrose | $(i)$ |
$\beta$ -D-Galactose and $\beta$ -D-Glucose |
| $(b)$ | Lactose | $(ii)$ | $\alpha$ -D-Glucose and $\beta$ -D-Fructose |
| $(c)$ | Maltose | $(iii)$ | $\alpha$ -D-Glucose and $\alpha$ -D-Glucose |
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