Question
Given that $M=\left[\begin{array}{ll}2 & 0 \\ 1 & 2\end{array}\right]$ and $N=\left[\begin{array}{cc}2 & 0 \\ -1 & 2\end{array}\right]$, find $M+2 N$
✓
Answer
$\begin{aligned} & M=\left[\begin{array}{ll}2 & 0 \\ 1 & 2\end{array}\right] \\ & N=\left[\begin{array}{cc}2 & 0 \\ -1 & 2\end{array}\right] \\ & \therefore M+2 N=\left[\begin{array}{ll}2 & 0 \\ 1 & 2\end{array}\right]+2\left[\begin{array}{cc}2 & 0 \\ -1 & 2\end{array}\right] \\ & =\left[\begin{array}{ll}2 & 0 \\ 1 & 2\end{array}\right]+\left[\begin{array}{cc}4 & 0 \\ -2 & 4\end{array}\right] \\ & =\left[\begin{array}{ll}2+4 & 0+0 \\ 1-2 & 2+4\end{array}\right] \\ & =\left[\begin{array}{cc}6 & 0 \\ -1 & 6\end{array}\right] . \\ & \end{aligned}$
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