MCQ
Given that $\sin \theta=\frac{a}{b}$, then $\tan \theta$ is equal to
- A$\frac{b}{\sqrt{a^2+b^2}}$
- B$\frac{b}{\sqrt{b^2-a^2}}$
- C$\frac{a}{\sqrt{a^2-b^2}}$
- ✓$\frac{a}{\sqrt{b^2-a^2}}$
✓
Answer
Correct option: D.
$\frac{a}{\sqrt{b^2-a^2}}$
D
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