MCQ
Given that $\sqrt{4096}=64,$ the value of $\sqrt{4096}+\sqrt{40.96}$ is:
- A$74$
- B$60.4$
- C$64.4$
- ✓$70.4$
Given, $\sqrt{4096}=64$
So, $\sqrt{4096}+\sqrt{40.96}$
$=64+\sqrt{4096\times10^{-2}}$
$=64+\sqrt{4096}\sqrt{10^{-2}}$
$=64+64\times10^{-2}$
$=64+6.4=70.4$
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