Question
Given $\triangle\text{ABC}\sim\triangle\text{PQR},$ if $\frac{\text{AB}}{\text{PQ}}=\frac13,$ then $\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR)}}=$ _________.

Answer

Given $\triangle\text{ABC}\sim\triangle\text{PQR},$ if $\frac{\text{AB}}{\text{PQ}}=\frac13,$ then $\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR)}}=$ $\frac19.$ Solution:$\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR)}}=\frac{\text{(AB)}^2}{(\text{PQ})^2}(\frac13)^2=\frac19.$

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